Фридрих Мерц. Фото: IMAGO / Peter Hartenfelser / Global Look Press
思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。，推荐阅读heLLoword翻译官方下载获取更多信息
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OPPO Find N6 真机曝光：肉眼几乎看不到折痕